>
> So, the f-stop that I want would want on the camera would be the f#
> given by incident divided by the m+1?
>
>
> Effective f# = (m+1)*(marked f#), where m is magnification
> In stops, it's log((m+1)**2)/log(2)
Yes. Rearranging the 1st equation, you get.
marked f# = (Effective f#) / (m+1)
The effective f# is what the film will experience.
The marked f# is the lens marking.
Diffraction goes by the effective f#, so it's best to not go
past a value of f/16.
Paul
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